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Table.PositionOfAny

Tiek atgriezta tabulā esošas jebkuras norādītās rindas pozīcija vai pozīcijas.

Syntax​

Table.PositionOfAny(
    table as table,
    rows as list,
    optional occurrence as number,
    optional equationCriteria as any
) as any

Remarks​

Atgriež rindas(-u) pozīciju(-as) no table saraksta pirmā gadījuma rows. Ja nav atrasts neviens gadījums, tiek atgriezta vērtība -1.

  • table: ievades tabula.
  • rows: to tabulas rindu saraksts, kam jāatrod pozīcijas.
  • occurrence: [Neobligāti] norāda, kuri rindas gadījumi jāatgriež.
  • equationCriteria: [Neobligāti] kontrolē salīdzināšanu starp tabulas rindām.

Examples​

Example #1​

Atrodiet [a = 2, b = 4] vai [a = 6, b = 8] pirmā gadījuma pozīciju tabulā ({[a = 2, b = 4], [a = 6, b = 8], [a = 2, b = 4], [a = 1, b = 4]}).

Table.PositionOfAny(
    Table.FromRecords({
        [a = 2, b = 4],
        [a = 1, b = 4],
        [a = 2, b = 4],
        [a = 1, b = 4]
    }),
    {
        [a = 2, b = 4],
        [a = 6, b = 8]
    }
)

Result:

0

Example #2​

Atrodiet [a = 2, b = 4] vai [a = 6, b = 8] visu gadījumu pozīcijas tabulā ({[a = 2, b = 4], [a = 6, b = 8], [a = 2, b = 4], [a = 1, b = 4]}.

Table.PositionOfAny(
    Table.FromRecords({
        [a = 2, b = 4],
        [a = 6, b = 8],
        [a = 2, b = 4],
        [a = 1, b = 4]
    }),
    {
        [a = 2, b = 4],
        [a = 6, b = 8]
    },
    Occurrence.All
)

Result:

{0, 1, 2}

Category​

Table.Membership