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Table.PositionOfAny

返回任何指定的行在表中的一个或多个位置。

Syntax​

Table.PositionOfAny(
    table as table,
    rows as list,
    optional occurrence as number,
    optional equationCriteria as any
) as any

Remarks​

返回 rows 的列表在 table 中第一次出现的行位置。如果找不到该值，则返回 -1。

  • table: 输入表。
  • rows: 表中要查找其位置的行列表。
  • occurrence: *(可选)*指定要返回的行的出现次数。
  • equationCriteria: *(可选)*控制表行之间的比较。

Examples​

Example #1​

查找 [a = 2, b = 4] 或 [a = 6, b = 8] 在表 ({[a = 2, b = 4], [a = 6, b = 8], [a = 2, b = 4], [a = 1, b = 4]}) 中第一次出现的位置。

Table.PositionOfAny(
    Table.FromRecords({
        [a = 2, b = 4],
        [a = 1, b = 4],
        [a = 2, b = 4],
        [a = 1, b = 4]
    }),
    {
        [a = 2, b = 4],
        [a = 6, b = 8]
    }
)

Result:

0

Example #2​

查找 [a = 2, b = 4] 或 [a = 6, b = 8] 在表 ({[a = 2, b = 4], [a = 6, b = 8], [a = 2, b = 4], [a = 1, b = 4]} 中所有出现的位置。

Table.PositionOfAny(
    Table.FromRecords({
        [a = 2, b = 4],
        [a = 6, b = 8],
        [a = 2, b = 4],
        [a = 1, b = 4]
    }),
    {
        [a = 2, b = 4],
        [a = 6, b = 8]
    },
    Occurrence.All
)

Result:

{0, 1, 2}

Category​

Table.Membership