Table.FromColumns

从列和指定值的列表创建一个表。

Syntax

Table.FromColumns(
    lists as list,
    optional columns as any
) as table

Remarks

从包含嵌套列表以及列名和值的列表 lists 创建类型为 columns 的表。 如果某些列比其他列具有更多值，则当这些列可为 Null 时，缺少的值将使用默认值 "Null" 填充。

Examples

Example #1

从列表中的客户名称列表返回一个表。客户列表项中的每个值将成为一个行值，每个列表将成为一个列。

Table.FromColumns({
    {1, "Bob", "123-4567"},
    {2, "Jim", "987-6543"},
    {3, "Paul", "543-7890"}
})

Result:

Table.FromRecords({
    [Column1 = 1, Column2 = 2, Column3 = 3],
    [Column1 = "Bob", Column2 = "Jim", Column3 = "Paul"],
    [Column1 = "123-4567", Column2 = "987-6543", Column3 = "543-7890"]
})

Example #2

从给定的列列表和列名列表创建一个表。

Table.FromColumns(
    {
        {1, "Bob", "123-4567"},
        {2, "Jim", "987-6543"},
        {3, "Paul", "543-7890"}
    },
    {"CustomerID", "Name", "Phone"}
)

Result:

Table.FromRecords({
    [CustomerID = 1, Name = 2, Phone = 3],
    [CustomerID = "Bob", Name = "Jim", Phone = "Paul"],
    [CustomerID = "123-4567", Name = "987-6543", Phone = "543-7890"]
})

Example #3

创建一个表，其中每行的列数不同。缺失的行值为 null。

Table.FromColumns(
    {
        {1, 2, 3},
        {4, 5},
        {6, 7, 8, 9}
    },
    {"column1", "column2", "column3"}
)

Result:

Table.FromRecords({
    [column1 = 1, column2 = 4, column3 = 6],
    [column1 = 2, column2 = 5, column3 = 7],
    [column1 = 3, column2 = null, column3 = 8],
    [column1 = null, column2 = null, column3 = 9]
})

Category

Table.Table construction